《PHP應用:php實現文件預覽功能》要點:
本文介紹了PHP應用:php實現文件預覽功能,希望對您有用。如果有疑問,可以聯系我們。
PHP編程上一篇博客是上傳功能,本篇是上傳后圖片預覽和更改:
PHP編程
PHP編程
PHP編程
PHP編程代碼如下:
PHP編程1.yulan.php
PHP編程
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>無標題文檔</title>
<style type="text/css">
#yl{ width:200px; height:300px; background-image:url(images/timg1.jpg); background-size:200px 300px;}
#file{ width:200px; height:300px; float:left; opacity:0;}
</style>
</head>
<body>
<form id="sc" action="ylchuli.php" method="post" enctype="multipart/form-data" target="shangchuan">
<input type="hidden" name="tp" value="" id="tp" />
<div id="yl">
<input type="file" name="file" id="file" onchange="document.getElementById('sc').submit()" />
</div>
</form>
<iframe style="display:none" name="shangchuan" id="shangchuan">
</iframe>
</body>
<script type="text/javascript">
//回調函數,調用該方法傳一個文件路徑,改變背景圖
function showimg(url)
{
var div = document.getElementById("yl");
div.style.backgroundImage = "url("+url+")";
document.getElementById("tp").value = url;
}
</script>
</html>
PHP編程2.ylchuli.php
PHP編程
<?php
if($_FILES["file"]["error"])
{
echo $_FILES["file"]["error"];
}
else
{
if(($_FILES["file"]["type"]=="image/jpeg" || $_FILES["file"]["type"]=="image/png")&& $_FILES["file"]["size"]<1024000)
{
$fname = "./images/".date("YmdHis").$_FILES["file"]["name"];
$filename = iconv("UTF-8","gb2312",$fname);
if(file_exists($filename))
{
echo "<script>alert('該文件已存在!');</script>";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],$filename);
$delurl = iconv("UTF-8","gb2312",$_POST["tp"]);
unlink($delurl); //刪除文件
echo "<script>parent.showimg('{$fname}');</script>";
}
}
}
PHP編程以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支持維易PHP.
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