《PHP實例:PHP中round()函數(shù)對浮點數(shù)進(jìn)行四舍五入的方法》要點:
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PHP學(xué)習(xí)本文實例講述了PHP中round()函數(shù)對浮點數(shù)進(jìn)行四舍五入的辦法.分享給大家供大家參考.具體辦法如下:
PHP學(xué)習(xí)語法:round(x,prec)
參數(shù) |
描述 |
x |
可選,規(guī)定要舍入的數(shù)字. |
prec |
可選,規(guī)定小數(shù)點后的位數(shù). |
PHP學(xué)習(xí)說明:返回將 x 根據(jù)指定精度 prec(十進(jìn)制小數(shù)點后數(shù)字的數(shù)目)進(jìn)行四舍五入的結(jié)果,prec 也可以是負(fù)數(shù)或零(默認(rèn)值).
PHP學(xué)習(xí)提示和注釋
PHP學(xué)習(xí)注釋:php默認(rèn)不能正確處理類似 "12,300.2" 的字符串.
PHP學(xué)習(xí)注釋:prec 參數(shù)是在 php 4 中被引入的,實例代碼如下:
代碼如下:
<?php
*/
echo round(3.4);???????? //輸出3
echo "<br>";
echo round(3.5);???????? //輸出4
echo "<br>";
echo round(3.6);???????? //輸出4
echo "<br>";
echo round(3.6,0);???????? //輸出4
echo "<br>";
echo round(1.95583,2);??????? //輸出1.96
echo "<br>";
echo round(1241757,-3);??????? //輸出1242000
echo "<br>";
echo round(4.045,2);???????? //輸出4.05
echo "<br>";
echo round(4.055,2);???????? //輸出4.06
?
//使用stdround函數(shù)代替php的round函數(shù)
?>
?
代碼如下:
<?php
function?? stdround($num,?? $d=0)?
{?
????? return?? round($num?? +?? 0.0001?? /?? pow(10,?? $d),?? $d);?
}???
????????
echo?? "round(1.005,2)= ".round(1.005,2). "n ";?
echo?? "round(1.015,2)= ".round(1.015,2). "n ";?
echo?? "round(1.025,2)= ".round(1.025,2). "n ";?
echo?? "round(1.035,2)= ".round(1.035,2). "n ";?
echo?? "round(1.045,2)= ".round(1.045,2). "n ";?
echo?? "round(1.055,2)= ".round(1.055,2). "n ";?
echo?? "round(1.065,2)= ".round(1.065,2). "n ";?
echo?? "round(1.075,2)= ".round(1.075,2). "n ";?
echo?? "round(1.085,2)= ".round(1.085,2). "n ";?
echo?? "round(1.095,2)= ".round(1.095,2). "n ";
?
echo?? "stdround(1.005,2)= ".stdround(1.005,2). "n ";?
echo?? "stdround(1.015,2)= ".stdround(1.015,2). "n ";?
echo?? "stdround(1.025,2)= ".stdround(1.025,2). "n ";?
echo?? "stdround(1.035,2)= ".stdround(1.035,2). "n ";?
echo?? "stdround(1.045,2)= ".stdround(1.045,2). "n ";?
echo?? "stdround(1.055,2)= ".stdround(1.055,2). "n ";?
echo?? "stdround(1.065,2)= ".stdround(1.065,2). "n ";?
echo?? "stdround(1.075,2)= ".stdround(1.075,2). "n ";?
echo?? "stdround(1.085,2)= ".stdround(1.085,2). "n ";?
echo?? "stdround(1.095,2)= ".stdround(1.095,2). "n ";
?
$m=0.000000000000001;?
echo?? "n ";?
echo?? "round(1.005+{$m},2)= ".round(1.005+$m,2). "n ";?
echo?? "round(1.015+{$m},2)= ".round(1.015+$m,2). "n ";?
echo?? "round(1.025+{$m},2)= ".round(1.025+$m,2). "n ";?
echo?? "round(1.035+{$m},2)= ".round(1.035+$m,2). "n ";?
echo?? "round(1.045+{$m},2)= ".round(1.045+$m,2). "n ";?
echo?? "round(1.055+{$m},2)= ".round(1.055+$m,2). "n ";?
echo?? "round(1.065+{$m},2)= ".round(1.065+$m,2). "n ";?
echo?? "round(1.075+{$m},2)= ".round(1.075+$m,2). "n ";?
echo?? "round(1.085+{$m},2)= ".round(1.085+$m,2). "n ";?
echo?? "round(1.095+{$m},2)= ".round(1.095+$m,2). "n ";
?
echo?? "round(1.005,2)= ".round(1.005,2). "n ";?
echo?? "round(1.015,2)= ".round(1.015,2). "n ";?
echo?? "round(1.025,2)= ".round(1.025,2). "n ";?
echo?? "round(1.035,2)= ".round(1.035,2). "n ";?
echo?? "round(1.045,2)= ".round(1.045,2). "n ";?
echo?? "round(1.055,2)= ".round(1.055,2). "n ";?
echo?? "round(1.065,2)= ".round(1.065,2). "n ";?
echo?? "round(1.075,2)= ".round(1.075,2). "n ";?
echo?? "round(1.085,2)= ".round(1.085,2). "n ";?
echo?? "round(1.095,2)= ".round(1.095,2). "n ";
?>
PHP學(xué)習(xí)希望本文所述對大家的PHP程序設(shè)計有所贊助.
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