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PHP應(yīng)用經(jīng)常看到有新手問(wèn)PHP有沒(méi)有類似asp的left函數(shù)或right函數(shù),實(shí)現(xiàn)截取某字符串左邊或右邊開(kāi)始N個(gè)字符的函數(shù).答案當(dāng)然是有的.PHP中的substr函數(shù)就可以做的到,只不過(guò)PHP把二個(gè)函數(shù)合二為一了,這里再給大家分享一個(gè)更加優(yōu)秀的截取字符串的函數(shù).
代碼如下:
/**
???? * 辦法庫(kù)-截取字符串-【該函數(shù)作者未知】
???? * @param string? $string 字符串?
???? * @param int???? $length 字符長(zhǎng)度
???? * @param string? $dot??? 截取后是否添加...
???? * @param string? $charset編碼
???? * @return string
???? */
??? public function cutstr($string, $length, $dot = ' ...', $charset = 'utf-8') {
??????? if (strlen($string) <= $length) {
??????????? return $string;
??????? }
??????? $string = str_replace(array('&', '"', '<', '>'), array('&', '"', '<', '>'), $string);
??????? $strcut = '';
??????? if (strtolower($charset) == 'utf-8') {
??????????? $n = $tn = $noc = 0;
??????????? while ($n < strlen($string)) {
??????????????? $t = ord($string[$n]);??????????????? //ASCII?
??????????????? if($t == 9 || $t == 10 || (32 <= $t && $t <= 126)) {
??????????????????? $tn = 1; $n++; $noc++;
??????????????? } elseif (194 <= $t && $t <= 223) {
??????????????????? $tn = 2; $n += 2; $noc += 2;
??????????????? } elseif (224 <= $t && $t < 239) {
??????????????????? $tn = 3; $n += 3; $noc += 2;
??????????????? } elseif (240 <= $t && $t <= 247) {
??????????????????? $tn = 4; $n += 4; $noc += 2;
??????????????? } elseif (248 <= $t && $t <= 251) {
??????????????????? $tn = 5; $n += 5; $noc += 2;
??????????????? } elseif ($t == 252 || $t == 253) {
??????????????????? $tn = 6; $n += 6; $noc += 2;
??????????????? } else {
??????????????????? $n++;
??????????????? }
??????????????? if($noc >= $length) {
??????????????????? break;
??????????????? }
??????????? }
??????????? if ($noc > $length) {
??????????????? $n -= $tn;
??????????? }
??????????? $strcut = substr($string, 0, $n);
??????? } else {
??????????? for ($i = 0; $i < $length; $i++) {
??????????????? $strcut .= ord($string[$i]) > 127 ? $string[$i].$string[++$i] : $string[$i];
??????????? }
??????? }
??????? $strcut = str_replace(array('&', '"', '<', '>'), array('&', '"', '<', '>'), $strcut);
??????? return $strcut.$dot;
??? }
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