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本節內容:
mysql時間查詢語句
?MYSQL入門
本日
select * from 表名 where to_days(時間字段名) = to_days(now());?
昨天
?
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 時間字段名) <= 1?
7天
?
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)?
近30天
?
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名)MYSQL入門
本月
?
SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )?
上一月
?
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 時間字段名, ‘%Y%m’ ) ) =1?
同時,再附上 一個 mysql官方的相關documentMYSQL入門
#查詢本季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查詢上季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查詢今年數據
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查詢上年數據
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
?
查詢當前這周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢當前月份的數據
select name,submittime from enterprise?? where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的數據
select name,submittime from enterprise?? where? date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL? 1 MONTH),'%Y-%m')
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where pudate between 上月最后一天
and 下月第一天
where?? date(regdate)?? =?? curdate();
select?? *?? from?? test?? where?? year(regdate)=year(now())?? and?? month(regdate)=month(now())?? and?? day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30MYSQL入門
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